In row 2, the only cells which contain a 5 are those which are highlighted. Therefore, one of them must
have 5 as the solution. Exactly the same observation may be made about row 6.
If you now rotate your thinking through 90 degrees, you will conclude that in both column 2 and column 9, the 5
must appear as the solution in one of the highlighted cells. Looking at column 2 in particular, the 5 in C2-R9
cannot be part of the solution and can be removed. Fortunately, this leaves a 4 as the
Single Candidate
in C2-R9, and provides us with the solution for this cell.